What is the edge length of zinc blende?

We know the zinc blende structure is made of Zinc atoms and Sulphur atoms. The structure consists of a cubic lattice in which Sulphur atoms occupy corners and face centre sites while the Zinc atoms occupy half of the tetrahedral sites. And ‘a’ is the edge length of a unit cell. So, the option (D) is the correct option.

What is the coordination number of zinc blende?

4
In zinc blende (ZnS), the sulphide ions are anions and are face centered. It means it has a coordination number 4 while zinc are cation ions which are present in the tetrahedral voids which are alternate.

Why is ZnS tetrahedral?

Summary: Zinc blend is a compound that comes in two forms: sphalerite and wurtzite. These are characterized by a 1:1 stoichiometric ratio of Zinc to Sulfur. It maintains a tetrahedral arrangement in both forms….Introduction.

Site	Zn	S
Face	0	6(1/2) = 3
Corner	0	8(1/8) = 1
Total	4	4

Is graphite FCC or BCC?

List of lattice constants

Material	Lattice constant (Å)	Crystal structure
C (graphite)	a = 2.461 c = 6.708	Hexagonal
Si	5.431020511	Diamond (FCC)
Ge	5.658	Diamond (FCC)
AlAs	5.6605	Zinc blende (FCC)

What is the coordination number for bcc arrangement?

8
The body-centered cubic (bcc) has a coordination number of 8 and contains 2 atoms per unit cell.

Which compound could adopt the Antifluorite crystal structure?

Magnesium compounds such as Mg2X, where X can be one of the elements Si, Ge, Sn, or Pb, are said to have an antifluorite structure because the locations of the anions and cations are reversed relative to fluorite (an anti-structure); the anions occupy the FCC regular sites whereas the cations occupy the tetrahedral …

What is the name for ZnS?

Zinc sulfide (ZnS), a naturally occurring salt, is the main source of zinc. It has two common crystalline forms (polymorphs): Sphalerite (“zinc blende”), with a cubic crystal structure, is the form that predominates in nature.

How many tetrahedral holes are there in BCC?

So, bcc has 2 atoms, then the number of octahedral voids will be 2 and the total number of tetrahedral voids will be = 2 x 2 = 4.